Question

What is the equation of a line that contains the point (3, 5) and hasba slope of 3 in slope-intercept form?

Answer 1

y= 3x - 5

Explanation:

y= mx+b is slope-intercept form,

m= slope (3)

b= y-intercept (5)

Therefore, y = 3x - 5 is your form.

If you wanted to calculate it, you'd input the x value of 3, like y = 3^3 - 5 to find your slope intercept.