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Find the 6th term of the geometric sequence whose common ratio 1/3 and whose first term is 4

asked
User Lukbl
by
7.8k points

1 Answer

2 votes

Answer:

a6 = 4/243

Explanation:

We can represent the geometric sequence with
a_n=4((1)/(3))^(n-1), so the 6th term would be
a_6=4((1)/(3))^(6-1)=(4)/(243).

answered
User Alexmurray
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