Question

a ball is kicked with an initial velocity of 11.0 m/s in the horizontal direction and 17.0 m/s in the vertical direction. (assume the ball is kicked from the ground.) (a) at what speed (in m/s) does the ball hit the ground?

Answer 1

see below

Step-by-step explanation:

maximum height attained= u²/2g

= 17²/2*10 m

= 14.45 m

speed on hitting the ground= √2gh

= √2*10*14.45 m/s

= 17m/s

hence it will hit the ground with same speed with which it was projected if we neglect the air resistance.