Answer:
I only
Explanation:
any point and its coordinates is an ordered pair of (x, y).
in other words, we get the x value used for the function and the resulting y value.
if the equation is true for such a pair, then the point is on the line. if it is false, then not.
y = (-5/4)x + 5
(4, 0)
0 = (-5/4)×4 + 5 = -5 + 5 = 0
true.
(0, 5)
5 = (-5/4)×0 + 5 = 0 + 5 = 5
true.
y + 5 = (-5/4)(x - 4)
(4, 0)
0 + 5 = (-5/4)(4 - 4)
5 = (-5/4)×0 = 0
false.
so, II is not containing (4, 0).
therefore, only I is contains both points.