Answer:
5.88 moles
Step-by-step explanation:
At Standard Temperature and Pressure (STP), the conditions are defined as a temperature of 0°C (273.15 K) and a pressure of 1 atm. To calculate the number of moles of chlorine gas in 155.3 liters at STP, we can use the Ideal Gas Law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Substituting the known values:
P = 1 atm
V = 155.3 liters
R = 0.0821 L·atm/mol·K
T = 273.15 K
Solving for n:
n = (PV) / (RT) = (1 atm * 155.3 liters) / (0.0821 L·atm/mol·K * 273.15 K) = 5.88 moles
In conclusion, 155.3 liters of chlorine gas at STP would contain 5.88 moles of chlorine gas.