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Gas in a container is at a pressure of 1.6 x 10^5 Pa and a volume of 4.0 m^3. What is the work done by the gas if it expands at a constant pressure to twice its initial volume?

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Answer: W = 6.4 x 10^5

Explanation: W = P x AV +(1.6x10^5 PA)(4M)

W = 6.4 x 10^5

Gas in a container is at a pressure of 1.6 x 10^5 Pa and a volume of 4.0 m^3. What-example-1
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