Question

What is the solution set for this system of equations?

4x + y = -12
x − 5y = -3

help, please

Answer 1

(-3,0)

x = -3

y = 0

Explanation:

4x + y = -12

x − 5y = -3

Enter the second equation by -4

4x + y = -12

-4x + 20y = 12

21y = 0

y = 0

Now enter 0 for y

4x + 0 = -12

4x = -12

x = -3

Plug that info in

4(-3) + 0 = -12

-12 + 0 = -12

-12 = -12

Therefore x = -3 and y = 0

Answer 2

x = -3

y = 0

Explanation:

4x + y = -12

x − 5y = -3

Times the second equation by -4

4x + y = -12

-4x + 20y = 12

21y = 0

y = 0

Now put 0 back in for y and solve for x

4x + 0 = -12

4x = -12

x = -3

Let's check

4(-3) + 0 = -12

-12 + 0 = -12

-12 = -12

So, x = -3 and y = 0 is the correct answer.