Question

Implicitly differentiate xy + 2x +3x² = 4 with respect to x.

Need real answer please

Answer 1

Answer: y' = (-6x-y-2)/x

Work Shown:

xy + 2x + 3x^2 = 4

d/dx[ xy + 2x + 3x^2 ] = d/dx[4]

d/dx[ xy ] + d/dx[ 2x ] + d/dx[ 3x^2 ] = d/dx[4]

y + xy' + 2 + 6x = 0

xy' = -6x-y-2

y' = (-6x-y-2)/x

y' = (-6x-y-2)/x