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Find the equation of the line, in slope-intercept form, which has a slope of 2/3 and contains the point (3, -4).

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Answer:

The slope-intercept form of a line is y = mx + b, where m is the slope and b is the y-intercept.

To find the equation of the line with a slope of 2/3 and passing through the point (3, -4), we can plug in the point and the slope into the equation:

y = 2/3 * x + b

-4 = 2/3 * 3 + b

-4 = 2 + b

b = -6

So the equation of the line is:

y = 2/3 x - 6

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