Question

Two identical moving balls of mass 6 kg have clastic collisioa where the first ball was moving at $ m/s before collition. Find the initial velocity of the second ball if the kinetic energy of the system after collision is 75 j.

A-200 m/s
B-4m/s
C-6m/s
D-3 m/s

Answer 1

Answer: The correct answer is D-3 m/s.

Step-by-step explanation: To find the velocity of the second ball, we need to use the principle of conservation of kinetic energy.

The total kinetic energy before the collision is equal to the total kinetic energy after the collision.

Initial kinetic energy = $\frac{1}{2} * 6 * v^2$

Final kinetic energy = $\frac{1}{2} * 6 * 6 + \frac{1}{2} * 6 * v^2 = 75$

Solving for v, we get v = 3 m/s.