Question

If two times a positive number is added to one third of its square, the result is 9,find the number​

Answer 1

Explanation:

`2x+(1)/(3) x^(2) =9`

Move all terms to l.h.s.

`(1)/(3) x^(2) +2x-9=0`

Multiply everything by 3

`x^(2) +6x-27=0`

Factorize

`(x+ 9)(x-3 )=0`

therefore

`x+9=0` or
`x-3 =0`

x= -9 or x =3

Since x is a positive answer the answer must be

x=3