Question

A father is twice as old as his son. If half that son's age, plus 84, equals twice the fathers age, how old is each person?

let the sons age be x

i srsly dont understand how to make formulas for this question

Answer 1

father=40

son=20

Explanation:

We can start by using the information given to set up a system of equations.

First, we know that the father's age is twice the son's age, so we can write the equation:

father's age = 2 * son's age

Next, we know that half the son's age plus 84 equals twice the father's age, so we can write the equation:

(1/2) * son's age + 84 = 2 * father's age

Now we can substitute the first equation into the second equation to get:

(1/2) * son's age + 84 = 2 * (2 * son's age)

Solving for x

(1/2) * x + 84 = 4x

x=20

father = 2*20 = 40

son = 20

Answer 2

The son is 56, and the father is 112.

Explanation:

Formula:

1/2x+84=2x