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A larger integer is 2 less than 3 times a smaller integer. The sum of the integers is 18. Find the integers​

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Answer:Let's call the smaller integer "x" and the larger integer "y".

From the problem, we know that:

y = 3x - 2 (because the larger integer is 3 times the smaller integer minus 2)

x + y = 18 (because the sum of the integers is 18)

We can substitute the first equation into the second equation to get:

x + (3x - 2) = 18

4x - 2 = 18

4x = 20

x = 5

Now that we know that the smaller integer is 5, we can use the first equation to find the larger integer:

y = 3x - 2

y = 3(5) - 2

y = 13

So the smaller integer is 5 and the larger integer is 13.

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