Question

I need help with this one asap

Answer 1

`(1)/(4y^9)`

Explanation:

using the rule of exponents

•
`(a^m)/(a^n)` =
`(1)/(a^((n-m)) )`

`(y^(-3) )/(4y^(6) )`

=
`(1)/(4)` ×
`(y^(-3) )/(y^6)`

=
`(1)/(4)` ×
`(1)/(y^((6-(-3))) )`

=
`(1)/(4)` ×
`(1)/(y^((6+3)) )`

=
`(1)/(4y^9)`