Question

consider the two similar alkyl halides which compound will undergo e2 elimination at a faster rate and why?

Answer 1

In the case of two similar alkyl halides, the compound that will undergo E2 elimination at a faster rate is the one with less steric hindrance and a stronger base.

Step-by-step explanation:

In the case of two similar alkyl halides, the compound that will undergo E2 elimination at a faster rate is the one with less steric hindrance and a stronger base. Steric hindrance refers to the obstruction of the reaction by bulky substituents. A stronger base will be more effective at abstracting the proton during the elimination process. Therefore, the compound with less steric hindrance and a stronger base will exhibit a faster E2 elimination rate.

Answer 2

Answer: The compound reacts faster because C-H Bonds are easier to break

Step-by-step explanation:

C-H bond is easier to break thus making the compound eliminate at a faster rate