How do I prove ABCD to be a rectangle in algebra 1

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asked Jan 25, 2024 86.8k views

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BenC · Answer 1 · 2024-02-01T03:40:39+0000

Answer:

Because ABCD is a parallelogram, its opposite sides are equal. (matching angles of congruent triangles). DCB = 90o . Hence ABCD is rectangle, because it is a parallelogram with one right angle.

How do I prove ABCD to be a rectangle in algebra 1

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