Question

In ΔJKL, j= 18 cm, l= 70 cm and ∠L=36°. Find all possible values of ∠J, to the nearest degree

Answer 1

Answer: 9∘

Explanation:

sinA/a = sinB/b

Answer 2

This is a straight application of the law of cosine: j2 = k2 + l2 -2 kl cos angle

You make the substitutions and do the arithmetic.