Question

PLEASE HELP! The height of a bottle rocket, in meters, is given by [tex]h(t) = -3t^{2} +36t+300, where t is measured in seconds. Compute the average velocity of the bottle rocket over the time interval t = 3 to t = 6.

Answer 1

63m/s hope it helps

Answer 2

63 m/s

Explanation:

h(3) = 3(3)² + 36(3) + 300 = 435

h(6) = 3(6)² + 36(6) + 300 = 624

v = Δh/Δt = (624m - 435m) / (6s - 3s) = 63 m/s