What is the probability that Louisville defeat Brianna at one game of rock paper scissors

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asked Aug 3, 2024 207k views

2 Answers

Wilson · Answer 1 · 2024-08-06T04:32:11+0000

Answer:
1/2
Explanation:
Let 'E' be the event where Louisville defeat Brianna at one game of rock paper scissors
Total number of outcomes- 2 (either Louisville will win or lose)
Number of favorable outcomes -1 (Louisville will win)
Therefore;
P(E) = favorable outcomes / total outcomes = 1/2

What is the probability that Louisville defeat Brianna at one game of rock paper scissors

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