How many grams of O2 will be formed from 28.9 moles of KCiO3

Question

asked Dec 17, 2024 212k views

1 Answer

IAhmed · Answer 1 · 2024-12-21T11:56:51+0000

Answer:

28.9 moles of KClO3 x (3 moles O2 / 2 moles KClO3) = 43.35 moles of O2

To convert moles to grams, you'll need to use the molar mass of O2, which is 32 g/mol.

43.35 moles x 32 g/mol = 1387.2 g of O2

So from 28.9 moles of KCiO3 , 1387.2 grams of O2 will be formed.