Answer: Given that 6log3 + 7 - 3loga = 0, we can start by isolating the variable a. To do this, we'll add 3loga to both sides:
6log3 + 7 = 3loga
Next, we'll divide both sides by 3:
2log3 + (7/3) = loga
Now we have loga on one side of the equation and a constant on the other. To find the possible values of a, we'll need to use the properties of logarithms.
We know that logb(x) = y is equivalent to b^y = x, so we can rewrite the equation as:
a = 3^(2log3 + (7/3))
To find the possible values of a, we'll need to evaluate the exponent on the right side of the equation. Since we don't know the value of log3, we can't find the exact value of a. However, we can say that the possible values of a are all the values that can be expressed as 3 raised to the power of (2log3 + (7/3))
Explanation: