Question

Find four consecutive even integers such that twice the sum of the second and third exceeds 3 times the first by 32.

Answer 1

• 20, 22, 24, 26

-------------------------------------

Let the integers be:

• x, x + 2, x + 4, x + 6

Twice the sum of the second and third exceeds 3 times the first by 32:

• 2(x + 2 + x + 4) = 3x + 32

Solve it for x:

• 2(2x + 6) = 3x + 32
• 4x + 12 = 3x + 32
• 4x - 3x = 32 - 12
• x = 20