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PLEASE HELP SUPER URGENT!!!!!

PLEASE HELP SUPER URGENT!!!!!-example-1
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User Clintm
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Answer 3:

At the end of the first hour, there would be 5 amoebas from the first group and 53=15 amoebas from the second group, a total of 5+15 = 20 amoebas.

At the end of the second hour, there would be 55 = 25 amoebas from the first group and 153 = 45 amoebas from the second group, a total of 25+45 = 70 amoebas.

At the end of the third hour, there would be 5^3 = 125 amoebas from the first group and 453 = 135 amoebas from the second group, a total of 125+135 = 260 amoebas.

Answer 4:

Using the formula N = No eRt where N is the population, No is the initial population, R is the exponential growth rate, and t is the time in days.

N = 104 * e^(0.11714) = 1042.813 = 292.56, rounded to the nearest rabbit would be 293.

So, the population of rabbits after 14 days would be 293.

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