Question

12 years ago, a mother was twice as old as her son. their present age are in the ratio of 14:9. find their present ages.​

Answer 1

The presents age of the mom is 42 years old, and of the son is 27 years old.

Explanation:

This question can be solved using a system of equations.

I am going to say that:

The mothers age is x.

The son's age is y.

12 years ago, a mother was twice as old as her son.

This means that:

`x - 12 = 2(y - 12)`

`x = 2y - 24 + 12`

`x = 2y - 12`

Their present age are in the ratio of 14:9.

This means that:

`(x)/(y) = (14)/(9)`

`14y = 9x`

Since
`x = 2y - 12`

`14y = 9(2y - 12)`

`18y - 108 = 14y`

`4y = 108`

`y = (108)/(4)`

`y = 27`

`x = 2*27 - 12 = 54 - 12 = 42`

The presents age of the mom is 42 years old, and of the son is 27 years old.