Question

-8x + 2 > 0Solve the following inequalities. Be sure to follow the rules for operations with signed numbers.

Answer 1

`-8x+2 > 0`

Subtract 2 from both sides:

`-8x+2-2 > 0-2`

`-8x > -2`

Divide both sides by -8:

`(-8x)/(-8) > (-2)/(-8)`

(Since we are dividing by a negative number, the sign will reverse)

`x < (1)/(4) \texttt{ or }x < 0.25`