Question

14. A father is twice as old as his son now. Ten years ago, the ratio of their ages was 5:2. Find their present ages.​

Answer 1

We can set up two equations to represent the information given in the problem:

F = 2S (where F is the father's present age and S is the son's present age)

(F - 10) / (S - 10) = 5/2

We can substitute equation 1 into equation 2:

(2S - 10) / (S - 10) = 5/2

We can cross-multiply and simplify to solve for S:

2S - 10 = 5S - 25

3S = 35

S = 35/3

S = 11.67

So the son is currently 11.67 years old. To find the father's age, we can use equation 1:

F = 2S

F = 2 * 11.67

F = 23.33

So the father is currently 23.33 years old.