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3 votes
CALCULATE THE [H3O+] FOR A URINE SAMPLE, WHICH HAS A PH OF 7.5

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User BennyM
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1 Answer

4 votes

use the formula [H3O+] = 10^-pH

plug in the pH [H3O+] = 10^-7.5

so [H3O+] = 3.162*10^-8 M

answered
User Tabrej Khan
by
8.7k points

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