Answer:
f(6)=23
Explanation:
f(n)=f(n-1)+3
f(1) becomes f(1-1)+3
f(1-1)+3 = 8
f(0) +3=8
f(0) = 5
=
f(2) = f(2-1)+3
f(2) = f(1)+3
f(2) = 8+3
f(2) = 11
f(3) = f(3-1)+3
f(3) = f(2) + 3
f(3) = 11+3
F(3) = 14
We can see that the sequence adds three to each prior value:
x Result
0 5
1 8
2 11
3 14
4 17
5 20
6 23
f(6) = 23