Answer:
Explanation:
I will assume you want the y-axis intercepts
arrange each equation into the form y = mx + b <==b is y-axis intercept
2x+y =1
y = -2x+1 <==== y axis intercept = 1
x -2y = 8
2y = x-8
y = 1/2x -4 <==== - 4 is the y axis intercept
Another way to find the y-axis intercept is to realize this occurs when x = 0
put x = 0 into the equations to find the intercept value
2x+y =1
2(0) + y = 1
y =1 <=====intercept
x-2y = 8
0 - 2y = 8
y = -4 <=====intercept
To find the where the two lines intersect, equate them
-2x+1 = 1/2x-4
5 = 2.5x
x = 2 then y = -2x+1 = -3 point of intersection (2,-3)