Question

a man jumps from a great height and falls freely to the earth. another man jumps from the same height 1 second later. how’s much are the two men separated by, 2 seconds after the second man jumps

Answer 1

24.53

Explanation:

d = (1/2)gt²

First man travels 1 sec + 2 sec = 3 sec

d = (1/2)(9.81 m/s²)(3 s)² = 44.15 m

Second man travels 2 sec

d = (1/2)(9.81 m/s²)(2 s)² = 19.62 m

Distance between the 2 men:

44.15 m - 19.62 m = 24.53 m