Answer:
The number of moles of acid that were neutralized can be found by multiplying the volume of the base (in liters) by its concentration (in moles/liter) and then multiplying that value by the stoichiometric coefficient of the acid in the balanced chemical equation for the neutralization reaction.
Step-by-step explanation:
To begin, we need to convert the volume of the base from milliliters to liters.
50.40 mL = 0.0504 L
Next, we can multiply the volume of the base (in liters) by its concentration (in moles/liter) to find the number of moles of base used in the titration.
0.0504 L * 0.542 M = 0.0272 moles
Since this is a neutralization reaction between a monoprotic acid and a strong base, the acid:base ratio is 1:1.
So the acid that has been neutralized is also 0.0272 moles.