Question

SnO2 (s) + 2 H2 (g) → Sn (s) + 2 H2O (l)

What mass of water is produced when 57.6g of SnO2 are consumed in the reaction above?

Answer 1

SnO2+2H2 - Sn +2H2O

50g of tin plus 32g of oxygen-36g of H2O

82g- 36g

57.6g- x

cross multiply

82xg= 2073.6g

xg = 2073.6/82

Xg= 25.28g

Therefore the mass of water consumed in the reaction is 25.28g