Question

If $x$ is a positive multiple of 8 and $x^2>100$, but $x<20$, what is $x$?

Answer 1

`$x=\boxed{16}$`

Explanation:

Since $x$ is a positive multiple of 8, it must be at least 8. Since $x^2>100$ and $x$ is at least 8, the only solution is $x=16$.

To verify this, note that $x=8$ does not satisfy the inequality $x^2>100$, but $x=16$ does, so $x=16$ is the only solution that works.

Therefore, $x=\boxed{16}$.

Answer 2

16

Explanation:

16 is a positive multiple of 8, in which 16²=256>100 and 16<20 are true statements.