Question

What is the area of a sector when theta=pi/12 radians and r =4

Answer 1

`(2\pi)/(3)\text{units}^2`

Explanation:

`\displaystyle A=(r^2\theta)/(2)=(4^2*(\pi)/(12))/(2)=(16\pi)/(24)=(2\pi)/(3)\text{units}^2`