How far will a force of 6 x 10^3N stretch a spring with spring constant 3 x 10^4 Nm-1 ?

Question

asked Mar 26, 2022 147k views

1 Answer

Anadi Misra · Answer 1 · 2022-04-01T23:57:05+0000

Answer:

0.2m

Step-by-step explanation:

F = 6 x 10^3N

k = 3 x 10^4 Nm-1

x = ?

from Hooke's law, F = kx

x = F/k = 6 x 10^3 ÷ 3 x 10^4 = 0.2m