Question

If a 3.1g ring is heated using 42 J, its temperature rises 17.9°C. Calculate the

specific heat capacity of the ring.

Answer 1

0.756 J/g°C

Step-by-step explanation:

The specific heat capacity of any material is defined as the quantity of heat (J) absorbed per unit of mass (kg) with an increase in temperature is 1 °C.

Specific heat capacity is defined as:

`S = (Q)/(m*deltaT)`

given, Q = 42J, m(mass) = 3.1g and ΔT = 17.9 °C

`S = (42.0)/(3.1*17.9)`

S = 0.756 J/g°C