Question

What are all the real zeros of the
function
y = −3(x + 1)³ + 9?

Answer 1

∛3 - 1 which is 0.44 to the nearest hundredth.

Explanation:

−3(x + 1)³ + 9 = 0

(x + 1)³ = -9/-3

(x + 1)³ = 3

x + 1 = ∛3

x = ∛3 - 1

= 0.44225

The cube root of 3 is positive, no negative real roots are possible.