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Which values of x make this equation true?

x^2+8x=-15

Which values of x make this equation true? x^2+8x=-15-example-1
asked
User Dablak
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8.8k points

1 Answer

2 votes

Answer: x = -5, -3

Explanation:

This is a quadratic function. First, we will move all terms to one side.

x² + 8x = -15

x² + 8x + 15 = 0

Next, we see that we cannot easily factor this equation. For this problem, we will use the quadratic formula. a = 1, b = 8, and c =15.


\displaystyle x=(-b\pm√(b^2-4ac) )/(2a)


\displaystyle x=(-8\pm√(8^2-4(1)(15)) )/(2(1))


\displaystyle x=(-8\pm√(64-60) )/(2)


\displaystyle x=(-8\pm√(4) )/(2)


\displaystyle x=(-8-2 )/(2),
\displaystyle x=(-8+2 )/(2)

x = -5, -3

We can also check our answer by substituting.

x² + 8x = -15 ➜ (-3)² + 8(-3) = -15 ✓

x² + 8x = -15 ➜ (-5)² + 8(-5) = -15 ✓

I know this is not one of your given answer options, but this is the solution to the given quadratic function. Was the question copied down correctly?

answered
User Klasske
by
7.8k points

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