Question

A student uses a string to whirl a 0.25-kilogram mass in a horizontal circular path that has a 0.80-meter radius. If the magnitude of the

centripetal force exerted on the mass with the string is 25 newtons, the speed of the mass is

Answer 1

the speed of the mass, we can use the equation:

v = sqrt(Fc*r/m)

where v is the speed, Fc is the centripetal force, r is the radius of the circular path, and m is the mass.

Plugging in the values, we get:

v = sqrt((25 N)(0.80 m)/(0.25 kg))
= sqrt(20 Nm/kg)
= sqrt(80 N*m/kg)
= 8.94 m/s

Therefore, the speed of the mass is approximately 8.94 m/s.