Question

How do I find the slope of The line that passes through (0,2) and (8,8) ? Please help and please help me know how to solve it so that I can show work and show that I understand how to do it I already know the answer is 3/4 but how do I get that

Answer 1

`General\ equation\ for\ line\ in\ slope\ intercept\ form:\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (0,2),\ (8,8)\ into\ equation\\\\ \left \{ {{2=0+b}\ \ \ \ \atop {8=8a+b\ }} \right.\\\\ \left \{ {{b=2}\ \ \ \ \atop {8=8a+b\}} \right.\\\\Substitution\ method\\\\8=8a+2\\\\8a=8-2\\\\8a=6\\\\a=(6)/(8)=(3)/(4)\\\\Answer\ y=(3)/(4)x+2. \ Slope\ is\ a=(3)/(4).`

Answer 2

`(0,2) , \ \ (8,8) \\\\ ]The \ formula \ for \ the \ slope \ of \ the \ straight \ line \ going \ through \\\\ the \ points (x _(1), y _(1))\ and \ (x _(2), y _(2)) \ is \ given \ by: \\ \\m= (y_(2)-y_(1))/(x_(2)-x_(1) )\\\\m= \frac{ 8-2} { 8-0 } =(6)/(8)=(3)/(4)`