Question

-3/7, -8/3 and -5/2,-2 slope

Answer 1

so the points are (-3/7,-8/3) and (-5/2,-2)
to find the slope do
(y2-y1)/(x2-x1)
(x,y)
x1=-3/7
y1=-8/3
x2=-5/2
y2=-2

subsitute

`(-2-( (-8)/(3) ))/( (-5)/(2) - (-3)/(7) )`
simplify by finding similar denomenators

`((-6)/(3)-( (-8)/(3) ))/( (-35)/(14) - (-6)/(14) )`

`((-6)/(3)( (8)/(3) ))/( (-35)/(14) + (6)/(14) )`
add

`((2)/(3))/( (-29)/(14))`
multiply top and bottom by


`((-28)/(87))/(1)`

`(-28)/(87)`
answer is
slope=
`(-28)/(87)`