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1 vote
100-99+98-97+96-95+...+8-7+6-5+4-3+2-1

asked
User Alfrekjv
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2 Answers

0 votes

x=100-99+98-97+96-95+...+8-7+6-5+4-3+2-1=\\\\=1+1+1+...+1+1+1+1=1\cdot n=n\\\\and\ \ \ 2=100-2\cdot(n-1)\ \ \ \Rightarrow\ \ \ 2n=100\ /:2\ \ \ \Rightarrow\ \ \ n=50\\\\x=50
5 votes

100-99+98-97+96-95+...+8-7+6-5+4-3+2-1\\\\=(100-99)+(98-97)+(96-95)+...+(4-3)+(2-1)\\\\=\underbrace{1+1+1+...+1}_(50)=\fbox{50}
100-99+98-97+96-95+...+8-7+6-5+4-3+2-1-example-1
answered
User Kevin Yang
by
7.8k points

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