Question

The perimeter of a rectangle is 36 and the length is twice the width.What are the dimensions of this rectangle and what is the area?

Answer 1

let l be the length and w be the width.

so 2l + 2w =36

also, l = 2w,

Putting the value for l in the first equation:

2(2w) + 2w = 36

4w + 2w = 26

6w = 36

w = 6

now solving for the length:

l = 2w

l = 2(6)

so the length will be 12, l = 12

So the width is 6. the length is 12.

and the area is lxw, so the area will be 72