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3 votes
Equation for slope that passes through (0,4) and (1,8)

asked
User Keturn
by
8.4k points

1 Answer

4 votes

m = (y_(2) - y_(1))/(x_(2) - x_(1)) = (8 - 4)/(1 - 0) = (4)/(1) = 4

y - y₁ = m(x - x₁)
y - 4 = 4(x - 0)
y - 4 = 4(x) - 4(0)
y - 4 = 4x - 0
+ 4 + 4
y = 4x + 4
answered
User Cooldude
by
8.2k points

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