System of equations Y=10+2z y=38-5z

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asked Jul 10, 2017 201k views

1 Answer

Christoph Eicke · Answer 1 · 2017-07-13T18:52:11+0000

y = 2z + 10
y = -5z + 38

2z + 10 = -5z + 38
+ 5z + 5z
7z + 10 = 38
- 10 - 10
7z = 28
7 7
z = 4
y = 2z + 10
y = 2(4) + 10
y = 8 + 10
y = 18
(z, y) = (4, 18)

System of equations Y=10+2z y=38-5z

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