Question

A system of equations is given below:

y = 4x − 3
2x + 7y = 41

Which of the following steps could be used to solve by substitution?

2(y = 4x-3) + 7y= 41

4x -3= 2x+ 7y

2x+ 7(4x- 3)=41

2(y= 4x-3)

Answer 1

y = 4x - 3
2x + 7y = 41

We need to substitute the first equation into the second equation. So, we would substitute y in the second equation with 4x -3.

2x + 7(4x -3) = 41

This would be answer choice C. 2x + 7(4x - 3) = 41.

Answer 2

Solving by substitution:

y = 4x - 3

2x + 7y = 41

Let us substitute the first equation y = 4x - 3 into the second.

2x + 7y = 41

2x + 7(y = 4x -3) = 41

2x + 7(4x -3) = 41

So that's the third option.

I hope this helps.