Question

The area of a rectangular sign is 36 square meters. If the length of the sign is one meter more than twice the width, then what is the width of the sign?

Answer 1

`l-length\\w-width\\\\2w=l-1\ \ \ \ \ /:2\\\\w=(l-1)/(2)\\\\Area:A=w* l;\ A=36\ m^2\\\\w* l=36\\\\put\ w=(l-1)/(2)\ into\ an\ equation\ w* l=36:\\\\(l-1)/(2)* l=36\ \ \ \ \ \ /*2`


`(l-1)* l=72\\\\l^2-l-72=0\\\\l^2-9l+8l-72=0\\\\l(l-9)+8(l-9)=0\\\\(l-9)(l+8)=0\iff l-9=0\ or\ l+8=0\\\\l=9\ or\ l=-8 < 0\\\\l=9\ m\ then\ w=(9-1)/(2)=(8)/(2)=4\ (m)\\\\Answer:The\ width\ of\ the\ sign\ equal\ 4m.`