Question

The element carbon (C) is most likely to form covalent bonds with the element beryllium (Be). krypton (Kr). selenium (Se). sodium (Na).

Answer 1

Answer: Option (c) is the correct answer.

Step-by-step explanation:

Atomic number of carbon is 6 and its electronic configuration is 2, 4. So, in order to complete its octet, it requires 4 more electrons.

Therefore, carbon form covalent bonds, that is, it shares electrons with and electron deficient atom.

Krypton is a noble gas and has completely filled octet. So, it will neither give to share its electrons with carbon atom.

Whereas beryllium and sodium does not have enough valence electrons to share. Hence, they will not form bond with carbon atom.

On the other hand, selenium being a non-metal is electron deficient and therefore, in order to complete its octet it will share its electrons with carbon atom.

Thus, we can conclude that the element carbon (C) is most likely to form covalent bonds with the element selenium (Se).

Answer 2

The element that is most likely to form covalent bonds with carbon (C) is

Selenium (Se)

Explanation

Covalent bond is formed when there is sharing of electrons among two or more non metals.

Both carbon and selenium are non metals therefore they react to form a covalent bond by sharing electron.

Despite krypton been a non metal it does not form a covalent bond with carbon since krypton is inert ( non reactive).

Beryllium (Be) and sodium (Na) are metals therefore they form ionic bond with carbon instead of covalent bond.