Question

16. Find the perimeter and area of a rectangle with length 6ft. and width 4 ft.

Answer 1

P = (L+W)*2
⇒ P= (6+4)*2
⇒ P= 10*2
⇒ P= 20.

S= L*W
⇒ S= 6*4
⇒ S= 24

The perimeter and area of the rectangle is 20 ft and 24 ft^2 respectively~