asked 114k views
3 votes
If a system requires 150 j of input work and produces 123 J of output work, whats its effiency

asked
User Vinny M
by
7.8k points

1 Answer

3 votes

The effiency of a machine is

(output work or energy) / (input work or energy) .

For the system described in the question, that's

(123 J) / (150 J) = 0.82 = 82% .


answered
User Harsh Sureja
by
8.3k points